{"id":18507,"date":"2024-03-01T09:13:09","date_gmt":"2024-03-01T09:13:09","guid":{"rendered":"https:\/\/soicau3027.minhngocxoso.com\/?p=18507"},"modified":"2024-03-01T09:13:09","modified_gmt":"2024-03-01T09:13:09","slug":"cach-tinh-tong-giai-dac-biet-xo-so-chuan-xac","status":"publish","type":"post","link":"https:\/\/xsmbsoicaubachthu.com\/cach-tinh-tong-giai-dac-biet-xo-so-chuan-xac\/","title":{"rendered":"C\u00e1ch t\u00ednh t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1 chu\u1ea9n x\u00e1c"},"content":{"rendered":"
T\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n b\u1eafc l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch soi, xem c\u1ea7u x\u1ed5 s\u1ed1 hi\u1ec7u qu\u1ea3 d\u00e0nh cho anh em mu\u1ed1n b\u1eaft l\u00f4 \u0111\u1ec1 hi\u1ec7u qu\u1ea3 n\u0103m 2024.<\/p>\n
Th\u00f4ng th\u01b0\u1eddng, c\u00e1ch b\u1eaft t\u1ed5ng l\u00f4 \u0111\u1ec1 hay \u0111\u01b0\u1ee3c \u00e1p d\u1ee5ng b\u00f3ng \u00e2m v\u00e0 b\u00f3ng d\u01b0\u01a1ng \u0111\u1ec3 t\u00ednh. C\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
T\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 0 th\u00ec h\u00f4m sau s\u1ebd \u0111\u00e1nh t\u1ed5ng l\u00e0 5. L\u00e0 1 th\u00ec \u0111\u00e1nh t\u1ed5ng l\u00e0 6, 2 th\u00ec d\u00e1nh t\u1ed5ng 7, 3 l\u00e0 8 c\u1ee9 nh\u01b0 v\u1eady theo b\u00f3ng c\u1ee7a ch\u00fang.<\/p>\n
C\u00e1ch b\u1eaft t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t theo Pascal l\u00e0 d\u00f9ng 5 s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 5 s\u1ed1 c\u1ee7a gi\u1ea3i nh\u1ea5t k\u1ebft h\u1ee3p l\u1ea1i v\u1edbi nhau \u0111\u1ec3 t\u1ea1o th\u00e0nh m\u1ed9t con s\u1ed1. Sau \u0111\u00f3 l\u1ea1i ti\u1ebfp t\u1ee5c c\u1ed9ng con s\u1ed1 v\u1eeba t\u1ea1o \u0111\u01b0\u1ee3c l\u1ea1i v\u1edbi nhau theo quy lu\u1eadt Pascal \u0111\u1ec3 t\u1ea1o n\u00ean m\u1ed9t con s\u1ed1 kh\u00e1c.<\/p>\n
C\u1ee9 nh\u01b0 v\u1eady c\u1ed9ng theo ki\u1ec3u 3 s\u1ed1 li\u00ean ti\u1ebfp l\u1ea1i v\u1edbi nhau cho t\u1edbi khi ch\u1ec9 c\u00f2n 2 s\u1ed1 cu\u1ed1i c\u00f9ng. Hai s\u1ed1 n\u00e0y ch\u00ednh l\u00e0 con s\u1ed1 c\u01a1 s\u1edf \u0111\u1ec3 nu\u00f4i l\u00f4 trong 3 ng\u00e0y, nh\u01b0 v\u1eady b\u1ea1n s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c con s\u1ed1 v\u1edbi t\u1ef7 l\u1ec7 tr\u00fang c\u01b0\u1ee3c cao nh\u1ea5t.<\/p>\n
\u0110\u1ed1i v\u1edbi nh\u1eefng gia \u0111\u00ecnh c\u00f3 truy\u1ec1n th\u1ed1ng ch\u01a1i l\u00f4 \u0111\u1ec1 x\u1ed5 s\u1ed1 th\u00ec s\u1ebd c\u00f3 b\u00ed quy\u1ebft gia truy\u1ec1n \u0111\u1ec3 soi t\u1ed5ng \u0111\u1ec1. Theo kinh nghi\u1ec7m c\u1ee7a nh\u1eefng ng\u01b0\u1eddi ch\u01a1i c\u00f3 \u00f4ng cha truy\u1ec1n \u0111\u1ea1t l\u1ea1i th\u00ec c\u00f3 chia s\u1ebb c\u00f4ng th\u1ee9c b\u1eaft t\u1ed5ng l\u00f4 \u0111\u1ec1 ch\u00ednh x\u00e1c nh\u1ea5t nh\u01b0 sau:<\/p>\n
Ng\u01b0\u1eddi ch\u01a1i khi n\u00e0y s\u1ebd l\u1ea5y 2 s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a 2 ng\u00e0y li\u00ean ti\u1ebfp nhau \u00e1p d\u1ee5ng theo c\u00e1ch t\u00ednh:<\/p>\n
C\u1ed9ng t\u1ea5t c\u1ea3 c\u00e1c con s\u1ed1 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 nh\u1ea5t l\u1ea1i v\u1edbi nhau ta s\u1ebd cho ra m\u1ed9t con s\u1ed1, con s\u1ed1 n\u00e0y s\u1ebd \u0111\u01b0\u1ee3c \u0111\u1eb7t t\u00ean l\u00e0 AB.<\/p>\n
Sau \u0111\u00f3 l\u1ea5y t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y th\u1ee9 hai l\u1ea1i v\u1edbi nhau ta s\u1ebd cho ra m\u1ed9t con s\u1ed1, con s\u1ed1 n\u00e0y s\u1ebd \u0111\u01b0\u1ee3c \u0111\u1eb7t t\u00ean l\u00e0 CD.<\/p>\n
Ti\u1ebfp theo s\u1ebd l\u1ea5y A +B => E v\u00e0 C + D => F.<\/p>\n
<\/p>\n
Sau khi \u0111\u00e3 cho ra c\u1ee5 th\u1ec3 m\u1ed9t con s\u1ed1 nh\u01b0 tr\u00ean th\u00ec ch\u00fang ta b\u1eaft \u0111\u1ea7u x\u00e9t c\u00e1c tr\u01b0\u1eddng h\u1ee3p:<\/p>\n
N\u1ebfu E < 10 v\u00e0 F < 10 th\u00ec ta s\u1ebd l\u1ea5y 10 \u2013 E => G v\u00e0 10 \u2013 F => H. T\u1eeb \u0111\u00f3, s\u1ebd cho ra \u0111\u01b0\u1ee3c 2 con s\u1ed1 c\u00f3 l\u00f4 l\u00e0 GH, HG \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
N\u1ebfu E < 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 10 \u2013 E => G v\u00e0 20 \u2013 F => K. Suy ra ta s\u1ebd cho ra \u0111\u01b0\u1ee3c 2 con s\u1ed1 c\u00f3 l\u00f4 l\u00e0 GK, KG \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp theo.<\/p>\n
N\u1ebfu E > 10 v\u00e0 F < 10 th\u00ec l\u1ea5y 20 \u2013 E => T v\u00e0 10 \u2013 F =? H. Nh\u01b0 v\u1eady, t s\u1ebd cho ra \u0111\u01b0\u1ee3c 2 con s\u1ed1 c\u00f3 l\u00f4 l\u00e0 TH, HT \u0111\u00e1nh cho ng\u00e0y ti\u1ebfp sau \u0111\u00f3.<\/p>\n
N\u1ebfu E > 10 v\u00e0 F > 10 th\u00ec l\u1ea5y 20 \u2013 E => T v\u00e0 20 \u2013 F => K. T\u1eeb \u0111\u00f3, ta c\u00f3 c\u1eb7p s\u1ed1 TK, KT \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y mai.<\/p>\n
N\u1ebfu tr\u01b0\u1eddng h\u1ee3p E, F \u0111\u1ec1u l\u00e0 0 th\u00ec c\u00e1c b\u1ea1n s\u1ebd \u0111\u00e1nh l\u00f4 k\u00e9p 00 cho ng\u00e0y h\u00f4m sau.<\/p>\n
\u0110\u1ec3 c\u00f3 th\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c con s\u1ed1 may m\u1eafn v\u1edbi t\u1ef7 l\u1ec7 tr\u00fang cao nh\u1ea5t th\u00ec ng\u01b0\u1eddi ch\u01a1i n\u00ean t\u00ednh to\u00e1n th\u1eadt k\u1ef9 t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t mi\u1ec1n b\u1eafc v\u00e0 c\u1ed1 g\u1eafng nu\u00f4i c\u00e1c c\u1eb7p l\u00f4 \u0111\u1ec1 t\u1ed1i \u0111a 3 ng\u00e0y. N\u1ebfu sau 3 ng\u00e0y m\u00e0 th\u1eafng th\u00ec ti\u1ebfp t\u1ee5c t\u00ednh to\u00e1n v\u00e0 ch\u01a1i ti\u1ebfp, c\u00f2n n\u1ebfu sau 3 ng\u00e0y thua th\u00ec d\u1eebng l\u1ea1i 3 ng\u00e0y sau r\u1ed3i h\u1eb5ng ch\u01a1i ti\u1ebfp.<\/p>\n