C\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1<\/strong> d\u1ef1a v\u00e0o gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a mi\u1ec1n B\u1eafc l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh l\u00f4 \u0111\u1ec1 \u0111\u00e3 \u0111\u01b0\u1ee3c r\u1ea5t nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i chuy\u00ean nghi\u1ec7p s\u1eed d\u1ee5ng h\u00e0ng ng\u00e0y. Trong b\u00e0i vi\u1ebft n\u00e0y, ch\u00fang t\u00f4i s\u1ebd \u0111\u01b0a ra c\u00e2u tr\u1ea3 l\u1eddi th\u1ecfa \u0111\u00e1ng nh\u1ea5t nh\u1eb1m gi\u1ea3i \u0111\u00e1p t\u1ea5t c\u1ea3 c\u00e1c c\u00e2u h\u1ecfi c\u00f3 li\u00ean quan \u0111\u1ebfn n\u00f3.<\/p>\n T\u1ed5ng l\u00e0 m\u1ed9t ph\u00e9p t\u00ednh c\u01a1 b\u1ea3n trong nh\u1eefng c\u00e1ch t\u00ednh to\u00e1n khoa h\u1ecdc. T\u1ed5ng s\u1ed1 ch\u00ednh l\u00e0 c\u1ed9ng c\u00e1c con s\u1ed1 l\u1ea1i v\u1edbi nhau \u0111\u1ec3 cho ra m\u1ed9t k\u1ebft qu\u1ea3 cu\u1ed1i c\u00f9ng. Th\u1ebf n\u00ean c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 c\u0169ng t\u01b0\u01a1ng t\u1ef1 nh\u01b0 c\u00e1ch t\u00ednh t\u1ed5ng s\u1ed1. Ch\u00fang ta ch\u1ec9 c\u1ea7n t\u00ednh t\u1ed5ng s\u1ed1 \u0111\u1ec1 xu\u1ea5t hi\u1ec7n trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00e0ng ng\u00e0y \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau.<\/p>\n <\/p>\n V\u00ed d\u1ee5: Ng\u00e0y 12\/03\/2024, ta c\u0169ng c\u00f3 th\u1ec3 th\u1ea5y gi\u1ea3i \u0111\u1eb7c bi\u1ec7t l\u00e0 46298, nh\u01b0 v\u1eady ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 b\u1eb1ng c\u00e1ch: 9 + 8 = 17.<\/p>\n Tuy r\u1eb1ng c\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 \u0111\u1ec3 \u0111\u01b0a ra \u0111\u01b0\u1ee3c nh\u1eefng con s\u1ed1 ch\u00ednh x\u00e1c nh\u1ea5t v\u00e0 c\u00f3 kh\u1ea3 n\u0103ng v\u1ec1 r\u1ea5t cao. Nh\u01b0ng b\u1ea1n c\u1ea7n ph\u1ea3i ch\u00fa \u00fd khi l\u1ef1a ch\u1ecdn c\u00e1ch n\u00e0y v\u00e0 h\u00e3y ghi nh\u1edb m\u1ed9t \u0111i\u1ec1u r\u1eb1ng c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 n\u00e0y ch\u1ec9 c\u00f3 hi\u1ec7u qu\u1ea3 trong v\u00f2ng t\u1eeb 2 \u0111\u1ebfn 3 th\u00e1ng. \u0110\u00e2y l\u00e0 m\u1ed9t c\u00e1ch b\u1eaft l\u00f4 \u0111\u1ec1 \u0111\u00e3 \u0111\u01b0\u1ee3c ch\u00fang t\u00f4i \u0111\u00fac k\u1ebft t\u1eeb kinh nghi\u1ec7m c\u1ee7a b\u1ea3n th\u00e2n v\u1edbi nh\u1eefng cao th\u1ee7 l\u00f4 \u0111\u1ec1 kh\u00e1c.<\/p>\n V\u1edbi c\u00e1ch t\u00ednh to\u00e1n n\u00e0y b\u1ea1n c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng \u0111\u01b0\u1ee3c c\u1ea3 nh\u1eefng k\u1ef3 quay \u1edf 3 mi\u1ec1n B\u1eafc \u2013 Trung \u2013 Nam. Nh\u01b0ng \u0111\u1ec3 c\u00e1c anh em c\u00f3 th\u1ec3 hi\u1ec3u m\u1ed9t c\u00e1ch d\u1ec5 d\u00e0ng h\u01a1n th\u00ec ch\u00fang t\u00f4i s\u1ebd s\u1eed d\u1ee5ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u1ee7a mi\u1ec1n B\u1eafc l\u00e0m chu\u1ea9n gi\u00fap cho b\u1ea1n d\u1ec5 h\u00ecnh dung h\u01a1n.<\/p>\n C\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 c\u00f9ng ch\u1ec9 n\u00ean s\u1eed d\u1ee5ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 c\u1ee7a ng\u00e0y ch\u1ee7 nh\u1ea5t \u0111\u1ec3 t\u0103ng kh\u1ea3 n\u0103ng chi\u1ebfn th\u1eafng l\u00ean cao h\u01a1n v\u00e0o nu\u00f4i li\u00ean ti\u1ebfp trong v\u00f2ng t\u1eeb 2 \u2013 3 ng\u00e0y \u0111\u1ec3 t\u0103ng \u0111\u1ed9 chi\u1ebfn th\u1eafng.<\/p>\n Ch\u00fang ta c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng c\u00e1c c\u00f4ng th\u1ee9c nh\u01b0 sau:<\/p>\n Ta l\u1ea5y con s\u1ed1 thu\u1ed9c gi\u1ea3i 7.2 \u0111\u1ec3 t\u00ednh t\u1ed5ng.<\/p>\n V\u00ed d\u1ee5 nh\u01b0 ng\u00e0y 12\/12\/2024 gi\u1ea3i 7.2 v\u1ec1 con 58 \u21d2 T\u1ed5ng c\u1ee7a n\u00f3 l\u00e0: 5 + 8 = 13<\/p>\n R\u1ed3i sau \u0111\u00f3 ta l\u1ea1i c\u1ed9ng ti\u1ebfp \u0111i\u1ec3m t\u1ed5ng c\u1ee7a n\u00f3 l\u00e0: 1 + 3 = 4<\/p>\n L\u1ea5y hi\u1ec7u c\u1ee7a \u0111i\u1ec3m t\u1ed5ng tr\u00ean ta \u0111\u01b0\u1ee3c: 3 \u2013 1 = 2<\/p>\n Cu\u1ed1i c\u00f9ng ta s\u1ebd c\u00f3 t\u1ed5ng 2 v\u00e0 t\u1ed5ng 4 \u0111\u1ec3 nu\u00f4i trong tu\u1ea7n ti\u1ebfp theo.<\/p>\n D\u1ef1a v\u00e0o c\u00e1ch t\u00ednh t\u1ed5ng kia ta th\u1ea5y \u0111\u01b0\u1ee3c ng\u00e0y 15\/12 c\u00f3 \u0111\u1ec1 v\u1ec1 95 \u21d2 T\u1ed5ng \u0111\u1ec3 l\u00e0: 9 + 5 = 14 v\u1ec1 t\u1ed5ng 4<\/p>\n Ng\u00e0y 16\/12 c\u00f3 \u0111\u1ec1 v\u1ec1 13 \u21d2 T\u1ed5ng \u0111\u1ec1 l\u00e0: 1+3 = 4 v\u1ec1 t\u1ed5ng 4<\/p>\n Ng\u00e0y cu\u1ed1i c\u00f9ng l\u00e0 18\/12 ta th\u1ea5y \u0111\u1ec1 v\u1ec1 02 \u21d2 T\u1ed5ng \u0111\u1ec3 l\u00e0: 0 + 2 = 2 v\u1ec1 t\u1ed5ng 2<\/p>\n B\u1ea1n c\u0169ng c\u00f3 th\u1ec3 \u0111\u00e1nh c\u00f4ng th\u1ee9c \u0111\u01b0\u1ee3c nh\u1eefng chuy\u00ean gia soi c\u1ea7u nghi\u00ean c\u1ee9u t\u1eeb c\u00f4ng th\u1ee9c n\u1ed5i ti\u1ebfng c\u1ee7a nh\u00e0 b\u00e1c h\u1ecdc Newton c\u00f3 t\u00ean g\u1ecdi l\u00e0 tam gi\u00e1c Pascal.<\/p>\n V\u1edbi c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec3 theo c\u00f4ng th\u1ee9c n\u00e0y c\u0169ng kh\u00e1 \u0111\u01a1n gi\u1ea3n, b\u1ea1n ch\u1ec9 c\u1ea7n d\u1ef1a v\u00e0o gi\u1ea3i nh\u1ea5t v\u00e0 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t trong b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 h\u00e0ng ng\u00e0y \u0111\u1ec3 t\u00ednh:<\/p>\n V\u00ed d\u1ee5: Ng\u00e0y h\u00f4m qua x\u1ed5 s\u1ed1 mi\u1ec1n B\u1eafc v\u1ec1, gi\u1ea3i \u0111\u1eb7c bi\u1ec7t: 65230 \u2013 gi\u1ea3i nh\u1ea5t: 56719. Ta h\u00e3y l\u1ea5y t\u1ea5t c\u1ea3 c\u00e1c con s\u1ed1 c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u00e0 gi\u1ea3i nh\u1ea5t th\u00e0nh m\u1ed9t d\u00e3y s\u1ed1 r\u1ed3i s\u1eafp x\u1ebfp theo c\u00f4ng th\u1ee9c Pascal.<\/p>\n <\/p>\n Ta s\u1ebd \u0111\u01b0\u1ee3c m\u1ed9t d\u00e3y s\u1ed1 nh\u01b0 sau: 6523056719. C\u1ed9ng l\u1ea7n l\u01b0\u1ee3t t\u1eeb tr\u00e1i sang ph\u1ea3i ta \u0111\u01b0\u1ee3c nh\u01b0 sau: 6 + 5, 5 + 2, 2 + 3, 3 + 0, 0 + 5, 5 + 6, 7 + 1, 1 + 9<\/p>\n \u21d2 Ta \u0111\u01b0\u1ee3c m\u1ed9t d\u00e3y s\u1ed1 m\u1edbi l\u00e0: 11 \u2013 7 \u2013 5 \u2013 3 \u2013 5 \u2013 11 \u2013 8 \u2013 10<\/p>\n L\u01b0u \u00fd nh\u1eefng con s\u1ed1 m\u00e0 ch\u00fang ta \u0111\u00e3 c\u1ed9ng l\u1ea1i m\u00e0 c\u00f3 t\u1ed5ng t\u1eeb 10 tr\u1edf l\u00ean th\u00ec ch\u1ec9 l\u1ea5y s\u1ed1 cu\u1ed1i c\u00f9ng. Ch\u00ednh v\u00ec th\u1ebf ta c\u00f3 \u0111\u01b0\u1ee3c c\u00e1c s\u1ed1: 1 \u2013 7 \u2013 5 \u2013 3 \u2013 5 \u2013 1 \u2013 8 \u2013 0.<\/p>\n Ch\u00fang ta l\u1ea1i ti\u1ebfp t\u1ee5c c\u1ed9ng t\u1ed5ng c\u00e1c con s\u1ed1 \u0111\u00f3 l\u1ea1i m\u1ed9t l\u1ea7n n\u1eefa ta \u0111\u01b0\u1ee3c: 1 + 7, 5 + 3, 5 + 1, 8 + 0 \u21d2 D\u00e3y s\u1ed1 m\u1edbi l\u00e0 8 \u2013 8 \u2013 6 \u2013 8<\/p>\n L\u1ea1i ti\u1ebfp t\u1ee5c c\u1ed9ng cho \u0111\u1ebfn khi c\u00f2n 2 con s\u1ed1 cu\u1ed1i c\u00f9ng. Ta c\u00f3: 8 + 8, 6 + 8 \u21d2 D\u00e3y s\u1ed1 m\u1edbi 16 \u2013 14. Ta l\u1ea5y 2 s\u1ed1 cu\u1ed1i l\u00e0 6 \u2013 4 \u0111\u1ec3 nu\u00f4i trong v\u00f2ng 2 \u2013 3 ng\u00e0y li\u00ean ti\u1ebfp v\u1edbi c\u1eb7p s\u1ed1 64 \u2013 46.<\/p>\n Tr\u00ean \u0111\u00e2y l\u00e0 nh\u1eefng c\u00e1ch chia s\u1ebb \u0111\u00e3 \u0111\u01b0\u1ee3c c\u00e1c chuy\u00ean gia soi c\u1ea7u c\u1ee7a ch\u00fang t\u00f4i t\u00ecm hi\u1ec3u v\u00e0 ph\u00e2n t\u00edch nh\u1eb1m gi\u00fap tr\u1ea3 l\u1eddi t\u1ea5t c\u1ea3 c\u00e1c c\u00e2u h\u1ecfi m\u00e0 c\u00e1c b\u1ea1n \u0111ang th\u1eafc m\u1eafc c\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1<\/strong>. N\u1ebfu b\u1ea1n c\u00f2n ch\u01b0a r\u00f5 v\u1ec1 v\u1ea5n \u0111\u1ec1 g\u00ec th\u00ec c\u00f3 th\u1ec3 comment cho ch\u00fang t\u00f4i \u0111\u1ec3 nh\u1eadn \u0111\u01b0\u1ee3c m\u1ed9t l\u1eddi gi\u1ea3i \u0111\u00e1p ch\u00ednh x\u00e1c nh\u1ea5t.<\/p>\n Tuy nhi\u00ean ,ch\u00fang t\u00f4i c\u0169ng c\u1ea7n ph\u1ea3i lu\u00f4n lu\u00f4n gi\u1eef m\u1ed9t c\u00e1i \u0111\u1ea7u l\u1ea1nh \u0111\u1ec3 c\u00f3 th\u1ec3 v\u1eadn d\u1ee5ng m\u1ed9t c\u00e1ch kh\u00e9o l\u00e9o nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p t\u00ednh to\u00e1n \u0111\u1ec3 cho \u0111\u1eddi nh\u1eefng con s\u1ed1 ch\u00ednh x\u00e1c nh\u1ea5t v\u1edbi t\u1ef7 l\u1ec7 v\u1ec1 cao nh\u1ea5t trong ng\u00e0y.<\/p>\n<\/div>\nT\u1ed5ng \u0111\u1ec1 l\u00e0 g\u00ec?<\/b><\/span><\/h2>\n
C\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 hi\u1ec7u qu\u1ea3 nh\u1ea5t<\/b><\/span><\/h2>\n
C\u00e1ch t\u00ednh t\u1ed5ng \u0111\u1ec1 mi\u1ec1n B\u1eafc<\/b><\/span><\/h3>\n
C\u00e1ch b\u1eaft t\u1ed5ng \u0111\u1ec1 h\u00e0ng ng\u00e0y<\/b><\/span><\/h3>\n
K\u1ebft lu\u1eadn<\/b><\/span><\/h2>\n
ch\u1ed1t s\u1ed1 bao \u0111\u1ec1 vip <\/span><\/h2>\n